Myanmar Earthquake--An Apple to the Moon--According to Einstein (and Newton)

 

how many joules in myanmar earthquake

The energy released by the Myanmar earthquake can be estimated using its magnitude of 7.7 on the moment magnitude scale (Mw). The formula to calculate the energy released during an earthquake is:

$$\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">E</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">=</span></span>{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">10</span></span>}}^{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">1.5</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">\times </span></span>\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">M</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">+</span></span>\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">4.8</span></span>}}$$

where $M$ is the magnitude. Substituting $M=7.7$:

$$\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">E</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">=</span></span>{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">10</span></span>}}^{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">1.5</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">\times </span></span>\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">7.7</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">+</span></span>\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">4.8</span></span>}}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">=</span></span>{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">10</span></span>}}^{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">16.35</span></span>}}\text{<span style="font-family: georgia;"><span style="font-size: medium;">\hspace{0.17em}</span></span>}\text{<span style="font-family: georgia;"><span style="font-size: medium;">joules</span></span>}$$

This corresponds to approximately $2.24\times {10}^{16}$ joules, or about 5.36 megatons of TNT equivalent energy.

https://www.perplexity.ai/search/how-many-joules-in-myanmar-ear-iu5AAK6KRH2vzs0c26K36A

how big a payload would 2.24×10(^16) joules transport to the moon

To calculate the payload mass equivalent to 2.24 × ${10}^{16}$ joules of energy, we use Einstein's equation:

$$\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">m</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">=</span></span>\frac{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">E</span></span>}}{{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">c</span></span>}}^{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">2</span></span>}}}$$

Where:

• $E=2.24\times {10}^{16}$ joules (energy),

• $c=3.00\times {10}^8$ m/s (speed of light in a vacuum).

Substituting the values:

$$\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">m</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">=</span></span>\frac{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">2.24</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">\times </span></span>{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">10</span></span>}}^{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">16</span></span>}}}{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">(</span></span>\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">3.00</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">\times </span></span>{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">10</span></span>}}^{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">8</span></span>}}{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">)</span></span>}^{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">2</span></span>}}}$$$$\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">m</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">=</span></span>\frac{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">2.24</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">\times </span></span>{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">10</span></span>}}^{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">16</span></span>}}}{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">9.00</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">\times </span></span>{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">10</span></span>}}^{\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">16</span></span>}}}$$$$\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">m</span></span>}<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">=</span></span>\mathrm{<span\; style="font-family:\; georgia;"><span\; style="font-size:\; medium;">0.249</span></span>}\text{<span style="font-family: georgia;"><span style="font-size: medium;">\hspace{0.17em}</span></span>}\text{<span style="font-family: georgia;"><span style="font-size: medium;">kg</span></span>}$$

Thus, the energy of 2.24 × ${10}^{16}$ joules could theoretically transport a payload of approximately 0.249 kilograms to the Moon17.

https://www.perplexity.ai/search/how-big-a-payload-would-2-24x1-eNZqEXhtQuSXG4SojUQpxw

what weighs approximately 0.249 kilograms

Approximately 0.249 kilograms is equivalent to 249 grams. Here are a few items that might weigh around this amount:

• A small to medium-sized apple typically weighs between 150 to 250 grams, so it could be close to this weight.

• A small bag of coffee or tea might also weigh around this amount.

• A small block of cheese, depending on the type and size, could weigh approximately 0.249 kilograms.

These are general examples, and the exact weight can vary based on the specific item and its size.

https://www.perplexity.ai/search/what-weighs-approximately-0-24-.OW_1LVMT4SQ5OZzqQEgYg

Image: https://www.britannica.com/biography/Isaac-Newton/Career

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